External command with system

• os.system
• system

import os

command = 'ls -l'

exit_code = os.system(command)

# $? on Linux/OSX
# %ERRORLEVEL% on Windows
print(exit_code)



exit_code = os.system('ls qqrq')
print(exit_code)
print(exit_code // 256)


exit_code = os.system('ls /root')
print(exit_code)
print(exit_code // 256)

If you wanted to list the content of a directory in an os independent way you'd use os.listdir('.') or you could use the glob.glob("*.py") function to have a subset of files.