Palindrome

---

An iterative and a recursive solution

examples/functions/palindrome.py

def is_palindrome(s):
    if s == '':
        return True
    if s[0] == s[-1]:
        return is_palindrome(s[1:-1])
    return False

def iter_palindrome(s):
    for i in range(0, int(len(s) / 2)):
        if s[i] != s[-(i+1)]:
            return False
    return True

print(is_palindrome(''))      # True
print(is_palindrome('a'))     # True
print(is_palindrome('ab'))    # False
print(is_palindrome('aa'))    # True
print(is_palindrome('aba'))   # True
print(is_palindrome('abc'))   # False

print()
print(iter_palindrome(''))      # True
print(iter_palindrome('a'))     # True
print(iter_palindrome('ab'))    # False
print(iter_palindrome('aa'))    # True
print(iter_palindrome('aba'))   # True
print(iter_palindrome('abc'))   # False